Python 基本操作
列表新增元素
1.
shopping_list = []
fruit = {"apple":3.2, "orange": 2.4, "banana": 1.7, "kiwi": 2.5}
for key in fruit:
List.append(key)
进制转换
int("0101",2) 二进制==>十进制
int("0101",3) 三进制==>十进制
hex(1024)
oct(1024)
bin(1024)
列表转set可去重
>>> l1 = ['b','c','d','b','c','a','a']
>>> l2 = set(l1)
>>> l2
{'c', 'a', 'd', 'b'}
Counter统计元素出现个数
from collections import Counter
a = [10, 8, 6, 7, 2, 8, 4, 10, 3, 7, 8, 4, 5, 7, 2, 2, 3, 8, 8, 9, 6, 2, 2, 7, 8, 7, 4, 8, 5, 2]
b = Counter(a)
print(b)
Counter({8: 7, 2: 6, 7: 5, 4: 3, 10: 2, 6: 2, 3: 2, 5: 2, 9: 1})
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作者:geerniya
来源:CSDN
原文:https://blog.csdn.net/geerniya/article/details/78638457
版权声明:本文为博主原创文章,转载请附上博文链接!
列表中的循环嵌套
>>> [i for i in range(4)]
[0, 1, 2, 3]
函数帮助
>>> help(print)
Help on built-in function print in module builtins:
print(...)
print(value, ..., sep=' ', end='\n', file=sys.stdout, flush=False)
Prints the values to a stream, or to sys.stdout by default.
Optional keyword arguments:
file: a file-like object (stream); defaults to the current sys.stdout.
sep: string inserted between values, default a space.
end: string appended after the last value, default a newline.
flush: whether to forcibly flush the stream.
>>> dir(print)
['__call__', '__class__', '__delattr__', '__dir__', '__doc__', '__eq__', '__format__', '__ge__', '__getattribute__', '__gt__', '__hash__', '__init__', '__init_subclass__', '__le__', '__lt__', '__module__', '__name__', '__ne__', '__new__', '__qualname__', '__reduce__', '__reduce_ex__', '__repr__', '__self__', '__setattr__', '__sizeof__', '__str__', '__subclasshook__', '__text_signature__']
打开文件
with open("test.txt") as test:
...
扩展阅读:Python 读写文件时不用 with 也不关闭文件,这样的风格好吗? - V2EX
二维数组排序
lst = [['G', 10], ['A', 22], ['S', 1], ['P', 14], ['V', 13], ['T', 7], ['C', 0], ['I', 219]]
>>> sorted(lst, key=lambda x: x[1], reverse=True)
[['I', 219], ['A', 22], ['P', 14], ['V', 13], ['G', 10], ...]
判断变量类型
>>> a = "foo"
>>> print(type(a))
<class 'str'>
>>> isinstance(a, str)
True
divmod除法
>>> 100//3
33
>>> 100%3
1
>>> div, mod = divmod(100,3) #整数,余数
>>> print(div, mod)
33 1
字符串倒序
>>> s1 = "apple"
>>> s2 = "".join(reversed(s1))
>>> s2
'elppa'
eval()函数
>>> x = 5
>>> t = 3
>>> eval(x+t)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: eval() arg 1 must be a string, bytes or code object
>>> eval("x+t")
8